Generate random Ascii characters

[ixGAMEOVERxixx]

VB.net

 

Use this code to generate random ascii chars, (CODE BY SLIPSTREAM)

 

Dim Random As New Random()
  TextBox1.Text = Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90))

And etc...

Edited June 20, 2009 by ixGAMEOVERxixx

[iBotPeaches]

One thing you can merge multiple declarations if its the same type.

 

Dim RandomNumber1, RandomNumber2, RandomNumber3, RandomNumber4 As Integer

 

 

Maybe you can directly put the RandomClass.Next in the Chr instead of the variable you made, not sure though.

[Dark Slipstream]

:S

 

VB.NET
  
  Dim Random As New Random()
  TextBox1.Text = Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90))

 

C#

 Random Rnd = new Random();
  TextBox1.Text = Convert.ToString(Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)));

Edited June 20, 2009 by Dark Slipstream

[XeNoS]

Thanks