Thanks to, Peaches & dennijr
This is the code that worked for me:
Process.Start(Application.StartupPath & "\apps\test.txt")
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I'm making a program that is basicly a AIO. I have a code where it open's the program i want, ete.
I'm using this code:
System.Diagnostics.Process.Start("test.txt")
But i don't want the program\files to be in the same folder as the .exe
I want it like this, and when i do this i get a ERROR
System.Diagnostics.Process.Start("apps\test.txt")
Here is what i want it to be/work like:
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So, my question is; how do i fix this?
Edited by i7m, 05 March 2010 - 03:11 PM.