3 replies to this topic

[ixGAMEOVERxixx]

VB.net

Use this code to generate random ascii chars, (CODE BY SLIPSTREAM)

Dim Random As New Random()
   TextBox1.Text = Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90))

And etc...

Edited by ixGAMEOVERxixx, 20 June 2009 - 02:58 PM.

[iBotPeaches]

One thing you can merge multiple declarations if its the same type.

Dim RandomNumber1, RandomNumber2, RandomNumber3, RandomNumber4 As Integer

Maybe you can directly put the RandomClass.Next in the Chr instead of the variable you made, not sure though.

[Dark Slipstream]

:S

VB.NET
   
   Dim Random As New Random()
   TextBox1.Text = Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90))

C#
 
  Random Rnd = new Random();
   TextBox1.Text = Convert.ToString(Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)) & Chr(Random.Next(65, 90)));

Edited by Dark Slipstream, 20 June 2009 - 02:04 PM.

[XeNoS]

Thanks